Some string functions used in Axapta:

How to find a string in Ax:

Syntax:

int strFind(
    str _text,
    str _characters,
    int _position,
    int _number)

Ex:
strFind(“abcdef”, “D”, 3, 02) //Returns 4.

strFind(“abcdef”, “Bf”, 3, -2) //Returns 2.

strFind(“abcdef”, “Z”, 3, 2) //Returns 0.

strFind("ABCDEFGHIJ","KHD",1,10); //Returns the value 4 (the position where "D" was found).

strFind("ABCDEFGHIJ","KHD",10,-10); //Returns the value 8 (the position where "H" was found).

How to search a specific character in String Ax:

Syntax:

int strScan(   str _text1, str _text2,    int _position,    int _number)

Ex:

//find the current item
    workingItem = Tree.getItem(Tree.getSelection());
    objectId = workingItem.text(); //objectId = "OBJ-0000021: Object Test 1- OBJ"
   
    super();  
    found = strscan(objectId, ":", found, strlen(objectId));
    If (found!=0)
    {
        objectIdActual = subStr(objectId,1,found-1);
        select RecId from objectTable1
        Index ObjectIdx
            where objectTable1.ObjectID == objectIdActual;
        objectBOM.ValidTimeStateUpdateMode (ValidTimeStateUpdate::Correction);
        ttsBegin;
        select forUpdate validTimeState(dateToday) * from objectBOM
            where objectBOM.RecId == element.args().record().RecId; //mroobject.RecId;
        objectBOM.Object = objectTable1.RecId;
        objectBOM.update();
        ttsCommit;
    }

How to Retrieves part of a string in Ax:

syntax:
str subStr(str _text, int _position, int _number)

Ex:

subStr("ABCDEFGHIJ",3,5); //Returns the string “CDEFG”.
subStr("ABCDEFGHIJ",7,-4); //Returns the string “DEFG”.
subStr("abcdef"),2,99) //Returns the string "cdef".
subStr("abcdef",2,3) //Returns the string "bcd".
subStr("abcdef",2,-3); //Returns the string "ab".

OR

void test()
{
str Name;
str Result;
;
Name="MED";
Result=substr(name,1,1);
info(strfmt("The original Name : %1,the sub string Result : %2",Name,Result));
}

Find Starting and ending positions using TextBuffer Class for SubStr():

int pos;
TextBuffer textBuffer;
; 
textBuffer = new TextBuffer();
textBuffer.setText("ABC DEF GHI JKL MNO ABC ABC");
pos = 0;

while (textBuffer.find("ABC",pos))
{
    print "String found at position: ", textBuffer.matchPos();
    pause;
    pos = textBuffer.matchPos()+1;
}

Regular Expressions in Ax:

http://mybhat.blogspot.in/2012/06/dynamics-ax-regular-expression-match.html